Solving brackets does not include forced distribution. Juxtaposition means multiplication, and as such, 2(3+5)² is the same as 2*(3+5)², so once the brackets result in 8, they’re solved.
Distribution needs to happen if you want to remove the brackets while there are still multiple terms inside, but it’s still a part of the multiplication. You can’t do it if there is an exponent, which has higher priority.
Your whole argument hangs on the misinterpretation of textbooks. This is what it feels like to argue against Bible fanatics lmao.
Tell you what, provide me a solver that says 2(3+5)² is 256 and you’ve won, it’s so easy no?
Solving brackets does not include forced distribution
Yes it does! 😂
Juxtaposition means multiplication,
No, it doesn’t. A Product is the result of Multiplication. If a=2 and b=3, axb=ab, 2x3=6, axb=2x3, ab=6. 3(x-y) is 1 term, 3x-3y is 2 terms…
as such, 2(3+5)² is the same as 2*(3+5)²
No it isn’t. 2(3+5)² is 1 term, 2x(3+5)² is 2 terms
so once the brackets result in 8
They don’t - you still have an undistributed coefficient, 2(8)
they’re solved
Not until you’ve Distributed and Simplified they aren’t
Distribution needs to happen if you want to remove the brackets
if you want to remove the brackets, YES, that’s what the Brackets step is for, duh! 😂 The textbook above says to Distribute first, then Simplify.
while there are still multiple terms inside
As in 2(8)=(2x8) and 2(3+5)=(6+10) is multiple Terms inside 😂
it’s still a part of the multiplication
Nope! The Brackets step, duh 😂 You cannot progress until all Brackets have been removed
which has higher priority.
It doesn’t have a higher priority than Brackets! 🤣
Your whole argument hangs on the misinterpretation of textbooks
says person who can’t cite any textbooks that agree with them, so their whole argument hangs on all Maths textbooks are wrong but can’t say why, 😂 wrongly calls Products “Multiplication”, and claimed that I invented a rule that is in an 1898 textbook! 🤣 And has also failed to come up with any alterative “interpretations” of “must” and “Brackets” that don’t mean, you know, must and brackets 😂
This is what it feels like to argue against Bible fanatics
says the Bible fanatic, who in this case can’t even show me what it says in The Bible (Maths textbooks) that agrees with them 😂
provide me a solver that says 2(3+5)² is 256 and you’ve won, it’s so easy no?
provide me a Maths textbook that says 8/2(1+3)=16 and you’ve won, it’s so easy no? 🤣
And in the meantime, here’s one saying it’s 1, because x(x-1) is a single Term…
Please find a Maths textbook that backs that up as being the correct answer. i.e. Exponents before Brackets. Should be easy, no? 🤣
Nobody has argued exponents should go before brackets.
I’m saying distribution being mandatory is an invented rule from your part.
No wonder you can’t produce such a simple request. I thought you had calculators that work “correctly”?
You did! 😂 You said 2(3+5)²=2(8)²=2(64), which is doing the Exponent when there are still unsolved Brackets 😂
You still haven’t explained how it’s in 19th Century textbooks if I “made it up”! 😂
If you don’t remember Roman Numerals either, that’s 1898
says person who still hasn’t produced a single textbook that supports anything that they say, and it’s such a simple request 😂
Solving brackets does not include forced distribution. Juxtaposition means multiplication, and as such,
2(3+5)²is the same as2*(3+5)², so once the brackets result in8, they’re solved.Distribution needs to happen if you want to remove the brackets while there are still multiple terms inside, but it’s still a part of the multiplication. You can’t do it if there is an exponent, which has higher priority.
Your whole argument hangs on the misinterpretation of textbooks. This is what it feels like to argue against Bible fanatics lmao.
Tell you what, provide me a solver that says
2(3+5)²is 256 and you’ve won, it’s so easy no?Yes it does! 😂
No, it doesn’t. A Product is the result of Multiplication. If a=2 and b=3, axb=ab, 2x3=6, axb=2x3, ab=6. 3(x-y) is 1 term, 3x-3y is 2 terms…
No it isn’t. 2(3+5)² is 1 term, 2x(3+5)² is 2 terms
They don’t - you still have an undistributed coefficient, 2(8)
Not until you’ve Distributed and Simplified they aren’t
if you want to remove the brackets, YES, that’s what the Brackets step is for, duh! 😂 The textbook above says to Distribute first, then Simplify.
As in 2(8)=(2x8) and 2(3+5)=(6+10) is multiple Terms inside 😂
Nope! The Brackets step, duh 😂 You cannot progress until all Brackets have been removed
It doesn’t have a higher priority than Brackets! 🤣
says person who can’t cite any textbooks that agree with them, so their whole argument hangs on all Maths textbooks are wrong but can’t say why, 😂 wrongly calls Products “Multiplication”, and claimed that I invented a rule that is in an 1898 textbook! 🤣 And has also failed to come up with any alterative “interpretations” of “must” and “Brackets” that don’t mean, you know, must and brackets 😂
says the Bible fanatic, who in this case can’t even show me what it says in The Bible (Maths textbooks) that agrees with them 😂
provide me a Maths textbook that says 8/2(1+3)=16 and you’ve won, it’s so easy no? 🤣
And in the meantime, here’s one saying it’s 1, because x(x-1) is a single Term…