Solving brackets does not include forced distribution
Yes it does! 😂
Juxtaposition means multiplication,
No, it doesn’t. A Product is the result of Multiplication. If a=2 and b=3, axb=ab, 2x3=6, axb=2x3, ab=6. 3(x-y) is 1 term, 3x-3y is 2 terms…
as such, 2(3+5)² is the same as 2*(3+5)²
No it isn’t. 2(3+5)² is 1 term, 2x(3+5)² is 2 terms
so once the brackets result in 8
They don’t - you still have an undistributed coefficient, 2(8)
they’re solved
Not until you’ve Distributed and Simplified they aren’t
Distribution needs to happen if you want to remove the brackets
if you want to remove the brackets, YES, that’s what the Brackets step is for, duh! 😂 The textbook above says to Distribute first, then Simplify.
while there are still multiple terms inside
As in 2(8)=(2x8) and 2(3+5)=(6+10) is multiple Terms inside 😂
it’s still a part of the multiplication
Nope! The Brackets step, duh 😂 You cannot progress until all Brackets have been removed
which has higher priority.
It doesn’t have a higher priority than Brackets! 🤣
Your whole argument hangs on the misinterpretation of textbooks
says person who can’t cite any textbooks that agree with them, so their whole argument hangs on all Maths textbooks are wrong but can’t say why, 😂 wrongly calls Products “Multiplication”, and claimed that I invented a rule that is in an 1898 textbook! 🤣 And has also failed to come up with any alterative “interpretations” of “must” and “Brackets” that don’t mean, you know, must and brackets 😂
This is what it feels like to argue against Bible fanatics
says the Bible fanatic, who in this case can’t even show me what it says in The Bible (Maths textbooks) that agrees with them 😂
provide me a solver that says 2(3+5)² is 256 and you’ve won, it’s so easy no?
provide me a Maths textbook that says 8/2(1+3)=16 and you’ve won, it’s so easy no? 🤣
And in the meantime, here’s one saying it’s 1, because x(x-1) is a single Term…
Yes it does! 😂
No, it doesn’t. A Product is the result of Multiplication. If a=2 and b=3, axb=ab, 2x3=6, axb=2x3, ab=6. 3(x-y) is 1 term, 3x-3y is 2 terms…
No it isn’t. 2(3+5)² is 1 term, 2x(3+5)² is 2 terms
They don’t - you still have an undistributed coefficient, 2(8)
Not until you’ve Distributed and Simplified they aren’t
if you want to remove the brackets, YES, that’s what the Brackets step is for, duh! 😂 The textbook above says to Distribute first, then Simplify.
As in 2(8)=(2x8) and 2(3+5)=(6+10) is multiple Terms inside 😂
Nope! The Brackets step, duh 😂 You cannot progress until all Brackets have been removed
It doesn’t have a higher priority than Brackets! 🤣
says person who can’t cite any textbooks that agree with them, so their whole argument hangs on all Maths textbooks are wrong but can’t say why, 😂 wrongly calls Products “Multiplication”, and claimed that I invented a rule that is in an 1898 textbook! 🤣 And has also failed to come up with any alterative “interpretations” of “must” and “Brackets” that don’t mean, you know, must and brackets 😂
says the Bible fanatic, who in this case can’t even show me what it says in The Bible (Maths textbooks) that agrees with them 😂
provide me a Maths textbook that says 8/2(1+3)=16 and you’ve won, it’s so easy no? 🤣
And in the meantime, here’s one saying it’s 1, because x(x-1) is a single Term…