No, because you can’t mathematically guarantee that pi contains long strings of predetermined patterns.
The 1.101001000100001… example by the other user was just that - an example. Their number is infinite, but never contains a 2. Pi is also infinite, but does it contain the number e to 100 digits of precision? Maybe. Maybe not. The point is, we don’t know and we can’t prove it either way (except finding it by accident).
Doesn’t, the binary pattern 10101010 dosen’t exists on that number, for example.
You can encode base 2 as base 10, I don’t think anyone is saying it exists in binary form.
Well it’s infinite so it has to I guess
Does this count:
No, because you can’t mathematically guarantee that pi contains long strings of predetermined patterns.
The 1.101001000100001… example by the other user was just that - an example. Their number is infinite, but never contains a 2. Pi is also infinite, but does it contain the number e to 100 digits of precision? Maybe. Maybe not. The point is, we don’t know and we can’t prove it either way (except finding it by accident).