• mindbleach@sh.itjust.works
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    1 day ago

    This is your own source - and it says, juxtaposition is just multiplication. It doesn’t mean E=mc2 is E=(mc)2.

    Throwing other numbers on there is like arguing 1+2 is different from 2+1 because 8/1+2 is different from 8/2+1.

    • This is your own source - and it says, juxtaposition is just multiplication

      inside brackets. Don’t leave out the inside brackets that they have specifically said you must use - “Parentheses must be introduced”! 🤣 BTW, this is a 19th Century textbook, from before they started calling them PRODUCTS 🙄

      E=mc2 is E=(mc)2

      No, it means E=mc² is E=mcc=(mxcxc)

      Throwing other numbers on there

      I have no idea what you’re talking about 🙄

      • mindbleach@sh.itjust.works
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        1 day ago

        Because BRACKETS - ab=(axb) BY DEFINITION

        “Parentheses must be introduced”!

        But you understand E=mc2 does not mean E=(mxc)2.

        This is you acknowledging that distribution and juxtaposition are only multiplication - and only precede other multiplication.

        In your chosen Introduction To Algebra, Chrystal 1817, on page 80 (page 100 of the PDF you used), under Exercises XII, question 24 reads (x+1)(x-1)+2(x+2)(x+3)=3(x+1)2. The answer on page 433 of the PDF reads -2. If 3(x+1)2 worked the way you pretend it does, that would mean 3=9.

        • 💡𝚂𝗆𝖺𝗋𝗍𝗆𝖺𝗇 𝙰𝗉𝗉𝗌📱@programming.dev
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          19 hours ago

          But you understand E=mc2 does not mean E=(mxc)2

          I already answered, and I have no idea what your point is.

          This is you acknowledging that distribution and juxtaposition are only multiplication

          Nope. It’s me acknowledging they are both BRACKETS 🙄

          E=mcc=(mxcxc) <== BRACKETS

          a(b+c)=(ab+ac) <== BRACKETS

          and only precede

          everything 😂

          • mindbleach@sh.itjust.works
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            19 hours ago

            Then why doesn’t the juxtaposition of mc precede the square?

            In your chosen book is the example you’re pestering moriquende for, and you can’t say shit about it.

            Another: Keys To Algebra 1-4’s answer booklet, page 19, upper right: “book 2, page 9” expands 6(ab)3 to 6(ab)(ab)(ab), and immediately after that, expands (6ab)3 to (6ab)(6ab)(6ab). The bullshit you made up says they should be equal.

            • 💡𝚂𝗆𝖺𝗋𝗍𝗆𝖺𝗇 𝙰𝗉𝗉𝗌📱@programming.dev
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              18 hours ago

              Then why doesn’t the juxtaposition of mc precede the square?

              For starters stop calling it “juxtaposition” - it’s a Product/Term. Second, as I already told you, c²=cc, so I don’t know why you’re still going on about it. I have no idea what your point is.

              In your chosen book

              You know I’ve quoted dozens of books, right?

              you can’t say shit about it

              Again I have no idea what you’re talking about.

              expands 6(ab)3 to 6(ab)(ab)(ab)

              Ah, ok, NOW I see where you’re getting confused. 6ab²=6abb, but 6(ab)²=6abab. Now spot the difference between 6ab and 6(a+b). Spoiler alert - the latter is a Factorised Term, where separate Terms have been Factorised into 1 term, the former isn’t. 2 different scenario’s, 2 different rules relating to Brackets, the former being a special case to differentiate between 6ab² and 6a²b²=6(ab)²

              P.S.

              is like arguing 1+2 is different from 2+1 because 8/1+2 is different from 8/2+1

              this is correct - 2+1 is different from 1+2, but (1+2) is identically equal to (2+1) (notice how Brackets affect how it’s evaluated? 😂) - but I had no idea what you meant by “throwing other numbers on there”, so, again, I have no idea what your point is

              • mindbleach@sh.itjust.works
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                18 hours ago

                Juxtaposition is key to the bullshit you made up, you infuriating sieve. You made a hundred comments in this thread about how 2*(8)2 is different from 2(8)2. Here is a Maths textbook saying, you’re fucking wrong.

                Here’s another: First Steps In Algebra, Wentworth 1904, on page 143 (as in the Gutenberg PDF), in exercise 54, question 9 reads (x-a)(2x-a)=2(x-b)2. The answer on page 247 is x=(2b2-a2)/(4b-3a). If a=1, b=0, the question and answer get 1/3, and the bullshit you’ve made up does not.

                You have harassed a dozen people specifically to insist that 6(ab)2 does not equal 6a2b2. You’ve sassed me specifically to say a variable can be zero, so 6(a+b) can be 6(a+0) can just be 6(a). There is no out for you. This is what you’ve been saying, and you’re just fucking wrong, about algebra, for children.

                • 💡𝚂𝗆𝖺𝗋𝗍𝗆𝖺𝗇 𝙰𝗉𝗉𝗌📱@programming.dev
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                  16 hours ago

                  Juxtaposition is key to the bullshit you made up

                  Terms/Products is mathematical fact, as is The Distributive Law. Maths textbooks never use the word “juxtaposition”.

                  You made a hundred comments in this thread about how 2*(8)2 is different from 2(8)2

                  That’s right. 1/2(8)²=1/256, 1/2x8²=32, same difference as 8/2(1+3)=1 but 8/2x(1+3)=16

                  Here is a Maths textbook saying, you’re fucking wrong

                  Nope! It doesn’t say that 1/a(b+c)=1/ax(b+c). You’re making a false equivalence argument

                  Here’s another:

                  Question about solving an equation and not about solving an expression. False equivalence again.

                  You have harassed a dozen people specifically to insist that 6(ab)2 does not equal 6a2b2

                  Nope! I have never said that, which is why you’re unable to quote me saying that. I said 6(a+b)² doesn’t equal 6x(a+b)², same difference as 8/2(1+3)=1 but 8/2x(1+3)=16

                  You’ve sassed me specifically to say a variable can be zero, so 6(a+b) can be 6(a+0) can just be 6(a).

                  That’s right

                  There is no out for you

                  Got no idea what you’re talking about

                  This is what you’ve been saying

                  Yes

                  you’re just fucking wrong

                  No, you’ve come up with nothing other than False Equivalence arguments. You’re taking an equation with exponents and no division, and trying to say the same rules apply to an expression with division and no exponents, even though we know that exponent rule is a special case anyway, even if there was an exponent in the expression, which there isn’t. 🙄

                  about algebra, for children

                  For teenagers, who are taught The Distributive Law in Year 7

                  • mindbleach@sh.itjust.works
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                    16 hours ago

                    I have never said that, which is why you’re unable to quote me saying that.

                    1/2(8)²=1/256

                    That’s you saying it. You are unambiguously saying a(b)c somehow means (ab)c=acbc instead of abc, except when you try to nuh-uh at anyone pointing out that’s what you said. Where the fuck did 256 come from if that’s not exactly what you’re doing?

                    You’re allegedly an algebra teacher, snipping about terms I am quoting from a textbook you posted, and you wanna pretend 2(x-b)2 isn’t precisely what you insist you’re talking about? Fine, here’s yet another example:

                    A First Book In Algebra, Boyden 1895, on page 47 (49 in the Gutenberg PDF), in exercise 24, question 18 reads, divide 15(a-b)3x2 by 3(a-b)x. The answer on page 141 of the PDF is 5(a-b)2x. For a=2, b=1, the question and answer get 5x, while the bullshit you’ve made up gets 375x.

                    Show me any book where the equations agree with you. Not words, not acronyms - an answer key, or a worked example. Show me one time that published math has said x(b+c)n gets an xn term. I’ve posted four examples to the contrary and all you’ve got is pretending not to see x(b+c)n right fuckin’ there in each one.