The Earth is sufficiently larger than anything one would drop off a tower that the weight of the dropped thing doesn’t matter at all
F=ma.
Two items of the same shape will have the same amount of air resistance. If they have significantly different masses, the two object experience commensurately different accelerations (or reduction in acceleration), even if the force is the same.
If you take a balloon full of tetrahexofluroride (a gas 6x the density of air) and a chunk of iron the exact same size and shape and throw them off a building, I guarantee the iron chunk will hit first.
How does your model of the universe explain the hammer and feather dropped on the moon by Apollo 15’s David Scott landed at the same time?
It’s called a vacuum, which is famous for not having air resistance. Y’know, the thing we’re talking about?
To perform the experiment properly on Earth where there is air resistance, you need to pick a shape and range of masses that minimize the effect of air resistance
F=ma.
Two items of the same shape will have the same amount of air resistance. If they have significantly different masses, the two object experience commensurately different accelerations (or reduction in acceleration), even if the force is the same.
If you take a balloon full of tetrahexofluroride (a gas 6x the density of air) and a chunk of iron the exact same size and shape and throw them off a building, I guarantee the iron chunk will hit first.
It’s called a vacuum, which is famous for not having air resistance. Y’know, the thing we’re talking about?
To perform the experiment properly on Earth where there is air resistance, you need to pick a shape and range of masses that minimize the effect of air resistance
You are wrong. Falling in a medium is slowed by buoyancy and drag
F=ma has nothing to do with it
Motherfucker, do you seriously not understand that buoyancy and drag are forces?!?!
Sit yo’ Dunning-Kruger ass down
Valid crashout. 🤣
https://en.wikipedia.org/wiki/Dunning–Kruger_effect
Without the m as the browser will decide for itself if it needs the mobile version.